1.

One mole of an ideal gas is taken through a cyclic process as shown in the V-T diagram. Which of the following statements is true ?

Answer»

The MAGNITUDE of work DONE by the gas is `RT_(0)ln2`.
Work done by gas is `V_(0)T_(0)`
Net work done by the gas is zero.
Work done by the gas is `2RT_(0)ln2`.

Solution :`W_(AB) = W_(CA) = 0` (as volume is constant)
`W_(DA) = RT_(0) ln((2V_(0))/(V_(0))) = RT_(0) ln2`
`W_(BC) = R(2T_(0))ln ((V_(0))/(2V_(0))) = -2RT_(0) ln 2`
Total work done by the gas is
`W = W_(AB) + W_(BC) + W_(CD) + W_(DA)`
`= 0 - 2RT_(0) ln 2 + 0 + RT_(0) ln 2 = -RT_(0) ln 2`
or `|W| = RT_(0) ln 2`


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