One mole of an ideal gas at STP occupies 22.4 L. What is the ratio of molar volume to atomic volume of a mole of hydrogen? Why is the ratio so large? Take size of hydrogen molecule to be 1 Å.

One mole of an ideal gas at STP occupies 22.4 L. What is the ratio of

1.	One mole of an ideal gas at STP occupies 22.4 L. What is the ratio of molar volume to atomic volume of a mole of hydrogen? Why is the ratio so large? Take size of hydrogen molecule to be 1 Å.
Answer» Solution :Å = `10^(-10)` m Atomic volume of 1 mole of hydrogen = Avogadro.s NUMBER `XX` volume of hydrogen molecule `= 6.023 xx 10^(23) xx 4/3 xx pi xx (10^(-10) m)^(3)` = 25.2 `xx 10^(-7) m^(3)` Molar volume = `22.4 L = 22.4 xx 10^(-3) m^(3)` `("Molar volume")/("Atomic volume") = 0.89 xx 10^(4) ~~ 10^(4)` This ratio is large because ACTUAL size of gas molecule is negligible in comparison to the inter molecular separation.