One mole of an ideal diatomic gas undergoes a transition from A to B along a path AB as shown in the figure, The change in internal energy of the gas during the transition is:

One mole of an ideal diatomic gas undergoes a transition from A to B a

1.	One mole of an ideal diatomic gas undergoes a transition from A to B along a path AB as shown in the figure, The change in internal energy of the gas during the transition is:
Answer» 20 KJ `-20` kJ 20 J `-12` kJ SOLUTION : `DeltaW=nC_V DeltaT` ….(1) but `DeltaT=T_2-T_1` `=(P_2V_2)/(NR)-(P_1V_1)/(nR) [ because T=(PV)/(nR)]` `=(P_2V_2-P_1V_1)/(nR)` Putting this VALUE in equation (1), `DeltaU=(nR)/(gamma-1) ((P_2V_2-P_1V_1)/(nR)) "" (because C_V=R/(gamma-1))` `=(P_2V_2 -P_1V_1)/(gamma-1)` `=((5xx4-2xx6)xx10^3)/(3/5-1) "" (because gamma=3/5)` `=((20-12)xx10^3)/(-2/5)` `=-(8xx10^3)/(2)xx5` =-20 kJ