One mole of a substance is cooled at the rate of `0.4 kJ min^(-1)` as shown in the graph. Curve `AB`, points `B` and `C` and curve `CD` represent respectively, the cooling of the liquid, start of freezing, completion of freezing and cooling of the solid based on this data. The entropy of fusion in `J molK^(-1)` is : A. `10`B. `20`C. `30`D. `40`

One mole of a substance is cooled at the rate of `0.4 kJ min^(-1)` as

1.	One mole of a substance is cooled at the rate of `0.4 kJ min^(-1)` as shown in the graph. Curve `AB`, points `B` and `C` and curve `CD` represent respectively, the cooling of the liquid, start of freezing, completion of freezing and cooling of the solid based on this data. The entropy of fusion in `J molK^(-1)` is : A. `10`B. `20`C. `30`D. `40`
Answer» Correct Answer - C The cooling shows fusion process for `30` minute `(40-10)` at `400K` `DeltaS=q/T=(0.4xx10^(3)xx30)/400=30 J`

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