One mole of a monoatomic ideal gas is taken through the cycle shown in figure. A→B: Adiabatic expansion B→C: Cooling at constant volume C→D: Adiabatic compression. D→A: Heating at constant volume The pressure and temperature at A,B,C and D are denoted by (PA,TA),(PB,TB),(PC,TC) and (PD,TD) respectively. Given TA=1000 K,PB=23PA and PC=13PA, the work done by the gas in the process A→B is [Take R=8.31 J/mol K]

One mole of a monoatomic ideal gas is taken through the cycle shown in

1.	One mole of a monoatomic ideal gas is taken through the cycle shown in figure. A→B: Adiabatic expansion B→C: Cooling at constant volume C→D: Adiabatic compression. D→A: Heating at constant volume The pressure and temperature at A,B,C and D are denoted by (PA,TA),(PB,TB),(PC,TC) and (PD,TD) respectively. Given TA=1000 K,PB=23PA and PC=13PA, the work done by the gas in the process A→B is [Take R=8.31 J/mol K]
Answer» One mole of a monoatomic ideal gas is taken through the cycle shown in figure. $A \to B :$ Adiabatic expansion $B \to C :$ Cooling at constant volume $C \to D :$ Adiabatic compression. $D \to A :$ Heating at constant volume The pressure and temperature at $A, B, C$ and $D$ are denoted by $(P_{A}, T_{A}), (P_{B}, T_{B}), (P_{C}, T_{C})$ and $(P_{D}, T_{D})$ respectively. Given $T_{A} = 1000 K, P_{B} = \frac{2}{3} P_{A}$ and $P_{C} = \frac{1}{3} P_{A}$ , the work done by the gas in the process $A \to B$ is [Take $R = 8.31 J/mol K$ ]