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One mole gas is first cooled from 300 K to 150 K at constant volume and then heated from 150 K to 300 K at constant pressure. The net heat absorbed by the gas is (a) zero (b) 150R (c) 300R (d) 450R |
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Answer» Correct Answer is: (b) 150R For the first process, at constant volume, ΔQ1 = nCv ΔT = Cv (-150). For the first process, at constant pressure, ΔQ2 = nCp ΔT = Cp (150). ΔQ1 + ΔQ2 = (Cp - Cv) 150 = 150R. |
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