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One litre of mixture of `CO` and `CO_(2)` is passed through red hot charcoal in tube. The new volume becomes 1.4 litre. Find out % composition of mixture by volume. All measurements are made at same `P` and `T` |
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Answer» On passing through a charcoal only, `CO_(2)` reduces to `CO`. `CO + C rarr` No reaction volume `a` `CO_(2) + C rarr 2 CO` Volume before reaction `b` `0` volume after reaction 0 `2b` As given `a + b =1` and `a + 2 b = 1.4` `:. b = 0.4 L` `implies % of b = (0.4)/(1) xx 100 = 40%` `:. a = 0.6 L` `implies % of a = (0.6)/(1) xx 100 = 60%` |
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