One litre of an ideal gas at a pressure of 6 atm undergoes an adiabatic expansion until its pressure drops to one atmosphere and volume increases to 2 litre. Find the word done during the process. [ gamma = 1.4].

One litre of an ideal gas at a pressure of 6 atm undergoes an adiabati

1.	One litre of an ideal gas at a pressure of 6 atm undergoes an adiabatic expansion until its pressure drops to one atmosphere and volume increases to 2 litre. Find the word done during the process. [ gamma = 1.4].
Answer» Solution :`V_(1) = 1` LITRE `= 10 6(-3) = m ^(3), P _(1) = 6 atm = 6 xx 1.013 xx 10 ^(5) Pa` `V_(2) = 2 ` litre `= 2 xx 10 ^(-3) m^(3), P _(1) = 1atm =1 xx 1. 013 xx 10 ^(5) Pa` Work DONE `= (1)?((gamma -1)) (P_(1) V _(1) - P _(2) V _(2))` `= (1)/(( 1.4 -1)) [6 xx 1. 013 xx10 ^(5) xx 10 ^(-3) - 1. 013 xx 10 ^(5) xx 2xx 10 ^(-3) ] = 1013 J`