One gram of charcoal adsorbs 100 mL of 0.5 M CH3COOH to form a mono-la – InterviewSolution

1.	One gram of charcoal adsorbs 100 mL of 0.5 M CH3COOH to form a mono-layer and thereby the molarity of acetic acid is reduced to 0.49 M. Calculate the surface area of the charcoal adsorbed by each molecule of acetic acid. Surface area of charcoal =3.01×102 m2/gm.
Answer» One gram of charcoal adsorbs $100 m L$ of $0.5 M C H_{3} C O O H$ to form a mono-layer and thereby the molarity of acetic acid is reduced to $0.49 M$ . Calculate the surface area of the charcoal adsorbed by each molecule of acetic acid. Surface area of charcoal $= 3.01 \times 10^{2} m^{2} / g m$ .

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