1.

One ferromagnetic substance has magnetic susceptibility chi_(m) at 27^(@) C temperature. At which temperature, it would become half ?

Answer»

`600^(@)C`
`300^(@) C`
`54^(@) C`
`327^(@) C`

SOLUTION :`chi_(m) prop (1)/( T)`
`therefore (chi_(m_(1) ) )/( chi_(m_(2)) ) = (T_(2) )/( T_(1))`
`(2 chi_(m_(1) ) )/(chi_(m_(1) ) ) = (T_2)/( 273+ 27) (because chi_(m_(2) ) = (chi_(m_(1 )))/( 2))`
`therefore T_(2) = 600 K`
`therefore t_(2) = T_(2) = 273 = 600 - 273 = 327 ^(@) C`


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