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One end of a U-tube containing mercury is connected to a suction pump and the other end to atmosphere. A small pressure difference is maintained between the two columns. Show that, when the suction pump is removed, the column of mercury in the U-tube executes simple harmonic motion. |
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Answer» Solution :When suction pump connected through one end of U-tube, the mercury depressed by h in one limb and in other arm mercury raised by 2h. The difference in height of mercury in both the limbs = 2Y and pressure of `P = 2hpg` in this arms. Here p= density of mercury and g is the acceleration DUE to GRAVITY. If the cross sectional area of arms is A, then force produced due to height of 2h, `F= PA` `=2hpg xxA = (2PGA)h` `therefore F propto h ""therefore F = kh` Where `k= 2pgA` is constant. This force is opposite to displacement, `F= -kh` Hence, restoring force acts on oscillation of mercury column is directly proportional to displacement and opposite to displacement. So the motion of mercury in U-tube is simple harmonic motion. |
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