One end of a long rope is tied to a fixed vertical pole. The rope is stretched horizontally with a tension 8 N. Let us consider the length of the rope to be along X-axis. A sample harmonic oscillator at x = 0 generates a transverse wave of frequency 100 Hz and amplitude 2 cm along the rope. Mass of a unit length of the rope is 20 gm/m. Ignoring the effect of gravity, answer the following questionsAssuming that the oscillator has its maximum negative displacement at t = 0, wave equation (function)for the wave can be expressed as

One end of a long rope is tied to a fixed vertical pole. The rope is s

1.	One end of a long rope is tied to a fixed vertical pole. The rope is stretched horizontally with a tension 8 N. Let us consider the length of the rope to be along X-axis. A sample harmonic oscillator at x = 0 generates a transverse wave of frequency 100 Hz and amplitude 2 cm along the rope. Mass of a unit length of the rope is 20 gm/m. Ignoring the effect of gravity, answer the following questionsAssuming that the oscillator has its maximum negative displacement at t = 0, wave equation (function)for the wave can be expressed as
Answer» `y = (0.02m) cos[ 8pi (RAD // m) x - 100pi (rad // s) t]` ` y = (0.02m) cos[ 10PI (rad // m) x - 200PI (rad // s) t]` `y = (0.02m) cos[10pi (rad // m) x - 200pi (rad // s) t-pi]` ` y = -(0.02m) SIN[8pi (rad /x m) x - 100pi (rad // s) t]` Answer :C

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