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One atom of an element weighs 1.79 2 into 10 power minus 22the atomic weight of element is​

Answer»

Answer:  108 g/mol.

Explanation:

According to AVOGADRO's LAW, 1 MOLE of every substance weighs equal to the molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

Given:

1 atom of an element weighs equal to 1.792\times 10^{-22}

Thus  to know the atomic weight , we need to FIND the weight of avogadro's number 6.023\times 10^{23} of particles.

Thus 1 atom of an element weighs= 1.792\times 10^{-22}

6.023\times 10^{23} atoms of a element weigh=\frac{1.792\times 10^{-22}{1}\times 6.023\times 10^{23}=108 g/mol

The atomic weight of element is​ 108 g/mol.


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