One angle of a triangle is 80° and remaining two angles are equal. Fi

1.	One angle of a triangle is 80° and remaining two angles are equal. Find the measure of each of the equal angles.
Answer» Let in ∆ABC, = 80° and ∠B = ∠C ∵∠A + ∠B +∠c = 180° ⇒ 80° +∠B + ∠B = 180° [∵ ∠A= 80° and 2C = ∠B] ⇒ 2∠B = 180° – 80° ⇒ ∠B = ( 100/2)= 50° Measure of each of the equal angles = 50°

One angle of a triangle is 80° and remaining two angles are equal. Find the measure of each of the equal angles.

Answer»

Let in ∆ABC, = 80° and ∠B = ∠C

∵∠A + ∠B +∠c = 180°

⇒ 80° +∠B + ∠B = 180°

[∵ ∠A= 80° and 2C = ∠B]

⇒ 2∠B = 180° – 80°

⇒ ∠B = ( 100/2)= 50°

Measure of each of the equal angles = 50°