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On this figure, BABC SODBC has equal base.Ã and BD are intersecting at the pointo:prove that: Area of DABD AAreaofABCD |
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Answer» ABD=1/2×b×h 1/2×DB×OABCD=1/2×b×h 1/2×DB×OC ABD/BCD=(1/2×DB×OA)/(1/2×DB×OC) =AO/OC
ABD=1/2×b×h 1/2×DB×OABCD=1/2×b×h 1/2×DB×OC ABD/BCD=(1/2×DB×OA)/(1/2×DB×OC) =AO/OC
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