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On reversing the digits of a digitsnumbernumber obtained as 9less than3 timethe orginal number. If differenceofthese2 number is 45 find theorginal sumber. |
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Answer» Answer: Step-by-step explanation:
→ Let the ten's digit be x → Let the unit's digit be y → HENCE the number would be 10x + y → Reversing the number, Reversed number = 10y + x → By given 10y + x = 3 (10x + y) - 9 10y + x = 30X + 3y - 9 10y -3y = 30x - x - 9 7y = 29 x - 9 29x - 7y - 9 = 0 ------(1) → Also by given 10y + x - (10x + y) = 45 10y + x -10x - y =45 9y - 9x = 45 → Dividing the whole equation by 9 y - x = 5 y = 5 + x ----(2) → Substitute equation 2 in equation 1 29x - 7(5 + x) - 9 = 0 29x - 35 - 7X - 9 = 0 22X - 44 = 0 22x = 44 x = 44/22 x = 2 → Hence the ten's digit is 2 → Substitute the value of x in 2 y = 5 + 2 y = 7 → The unit's digit is 7 → Hence the number is 2 × 10 + 7 The number = 20 + 7 The number = 27 → By the first case, 10y + x = 3 (10x + y) -9 10 × 7 + 2 = 3 (10 × 2 + 7) - 9 70 + 2 = 3 ( 20 + 7) -9 72 = 3 ( 27) - 9 72 = 81 - 9 72 = 72 → Difference of the reversed and orginal number = 45 10y + x - (10x + y) = 45 10 × 7 + 2 - (10 × 2 + 7) = 45 70 + 2 - (20 + 7) = 45 72 - 27 = 45 45 = 45 → Hence verified. |
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