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On one mole of gas at s.tp. is doubled and the temperature is raised to 546 K. What is theThe pressure)final volume of the gas? (one mole of a gas occupies a volume of 22.4 litres at stp.) |
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Answer» Step-by-step explanation: P1=760 MMHG P2=760×2=1520 V1=22.4L V2=? T1=273K T2=2×273=546K
By USING gas eqaution P1V1/T1 = P2V2/T2 760×22.4/273 = 1520×V2/546
V2= 760×224×546/273×1520×10 = 112/5 = 22.4×2 V2 =5017.6 HOPE THIS WILL HELP YOU |
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