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On mixing, heptane and octane form an ideal solution. At 373 K, the vapour pressure of the two liquid components ( heptane and octane) are 105 kPa and 45 kPa respectively. Vapour pressure of the solution obtained by mixing 25.0 g of heptane and 35 g of octane will be ( molar mass of heptane = 100 "g mol"^(-1) and of octane = 114 "g mol"^(-1) ): |
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Answer» 96.2 KPA `x_(h)=(0.25)/(0.25 + 0.307)=0.45` `:.x_(0)=1-0.45=0.55` `p=x_(h)p_(h)^(@)+x_(o)p_(o)^(@)` `=0.45xx105+0.55xx45` `=47.25+24.75=72` kPa |
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