1.

On mixing, heptane and octane form an ideal solution. At 373 K, the vapour pressure of the two liquid components ( heptane and octane) are 105 kPa and 45 kPa respectively. Vapour pressure of the solution obtained by mixing 25.0 g of heptane and 35 g of octane will be ( molar mass of heptane = 100 "g mol"^(-1) and of octane = 114 "g mol"^(-1) ):

Answer»

96.2 KPA
144.5 kPa
72.0 kPa
36.1 kPa

Solution :`n_(H)=0.307`
`x_(h)=(0.25)/(0.25 + 0.307)=0.45`
`:.x_(0)=1-0.45=0.55`
`p=x_(h)p_(h)^(@)+x_(o)p_(o)^(@)`
`=0.45xx105+0.55xx45`
`=47.25+24.75=72` kPa


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