On dissolving 3.24 g of sulphur in 40 g of benzene, boliling point of the solution was highter then that of benzene by 0.81 K. The molal elevation constant (K_(b)) for benzeneis 2.53 K kg mol^(-1). "What is the molecular formula of sulphur "("Atomic mass of" S=32 g mol^(-1))?

On dissolving 3.24 g of sulphur in 40 g of benzene, boliling point of

1.	On dissolving 3.24 g of sulphur in 40 g of benzene, boliling point of the solution was highter then that of benzene by 0.81 K. The molal elevation constant (K_(b)) for benzeneis 2.53 K kg mol^(-1). "What is the molecular formula of sulphur "("Atomic mass of" S=32 g mol^(-1))?
Answer» Solution :Calculation of molecular mas of sulphur `(S_(N))` `M_(B)=(K_(b)xxW_(b))/(DeltaT_(b)xxW_(A))` Mass of sulphur `(W_(b))=3.24g` `" Mass of benzene"(W_(A))=40g=0.04 kg` Molal elevetion constant `(K_(b))=2.53 K kg mol^(-1)` Elevation in BOILING point `(Delta T_(b))=0.81 K` `M_(B)=((2.53 K kg mol^(-1))XX(3.24 g))/((0.81 K)xx(0.04 kg))=253g mol^(-1)` Calcultion of molecular formula of sulphur. Gram atomic mass of sulphur =32 g `mol^(-1)` In `S_(n),nxx(32g mol^(-1))=253 g mol^(-1)` `n=((253 g mol^(-1)))/((32g mol^(-1)))=7.9~~8` Molecular formula of sulphur is `S_(8)`.