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On dissolving 3.24 g of sulphur in 40 g of benzene, boiling point ofsolution was higher than that of benzene by 0.81K (K_(b) = 2.53 K kg mol^(-1)). What is molecular formula of sulphur ? (Atomic mass s = 32 gmol^(-1)) |
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Answer» SOLUTION :`M_(B) = (K_(b) xx W_(b) xx 1000)/(Delta T_(b) xx W_(A)) = (2.53 xx 3.24 xx 10^(3))/(0.81 xx 40)` `= 253 g mol^(-1)` Let the molecular formula of sulphur = `S_(x)` Atomic MASS of sulphur = 32 Molecular mass = `32 xx x` 32 x = 253 `x = 7.91 = 8` Molecular formula of sulphur = `S_(S)` |
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