Saved Bookmarks
| 1. |
of the following figures, one side of a triangle has been produced. Find all the angles of thgle in each case.A50°(11)120° |
|
Answer» (I) <x = 125° - 50° <B = 75°(ii). 2x + x = 120° x = 40°<A = 2 × 40 = 80°<C = 40° A.75°B.2x=80° x=40° is the correct answer. x=40digree is a correct answer i) 75° and (ii) ? par copy me bana ke dekna padega x=40° it is right answer I think 20 is a right answer x is 80 degree to Q 1 and x is 120 degree to Q2 1.sum of exterior angle property angle A+angle B=125 degree 50+x=125x=125-50x=752.sum of exterior angle property angle A+angle C =120 degree 2x+x=1203x=120x=120÷3x=40 x=75degree because sum of two interior angle =exterior angle x=40° is the correct answer h i) angle DCB = 125°So angle ACB = 180° - 125° = 55°Now,x = 180° - (50° + 55°)x = 180° - 105°x = 75°ans = the value of x angle is 75°. ii) angle DBC = 120° So angle ABC = 180° - 120° = 60°Now , 2x + x + 60° = 180° 3x + 60° = 180°3x = 180° - 60°3x = 120° x = 120°/ 3x = 40° x = 40°then, 2x = 2 × 40° = 80°ans = The angles of ∆ ABC are 80° , 40° and 60° respectively x + 50°= 125°x = 125°- 50°x = 75° |
|