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Of sec A = 25/7, find the value of sin A |
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Answer» secA= HYPOTENUSE/ base secA=25/7 hyp=25;base=7 using Pythagoras theorem hypotenuse^2= perpendicular^2+ base^2 (25)^2= per^2+7^2 (perp)^2=576 perp= 24 sinA= perp/ hyp sinA =24/25 |
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