1.

Of sec A = 25/7, find the value of sin A​

Answer»

secA= HYPOTENUSE/ base

secA=25/7

hyp=25;base=7

using Pythagoras theorem

hypotenuse^2= perpendicular^2+ base^2

(25)^2= per^2+7^2

625=PERP^2+ 49

(perp)^2=576

perp= 24

sinA= perp/ hyp

sinA =24/25



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