Saved Bookmarks
| 1. |
Obtain the equation of frequency of stationary wave propuced in open pipe and show that all harmonics are possible in it. |
|
Answer» Solution :In open pipe antiodes are produced at both ends and CONSECUTIVE antinodes are obtained at `(lamda)/(2), lamda, (3lamda)/(2), …, (n lamda)/(2)` where,` n = 1,2,3,…` If wavelength is `lamda` for open pipe of length L, then stationary waves will only be produced if `L = ( n lamda )/(2)` `therefore lamda _(n) = (2L)/(n)` Frequency of stationlary waves in open pipe, `(v)/( v _(n )) = (2L)/(n) [ because v = lamda v implies lamda = (v)/(v ) ]` `therefore v _(n) = (nv)/(2L)...(1)` where v is wave SPEED. First 4 harmonics are shown for stationary waves in open pipe in figure, If wp place `n =1 `in equatin (1), then fundamental or first harmonic is obtained, `therefore v _(2) = (v)/(2L)` Second harmonic is obtained by putting `n =2` in equation (1), `therefore v _(2) = (2v )/( 2L) = v/L OR 2 ((v )/(2L)) = 2v _(1)` Accordingly by putting `n = 3,4 ,...,n` in equation (1), THIRD, fourth, `...n ^(th)` harmonic can be obtained and corresponding (n-1) overtones are obtained. |
|