Obtain the differential coefficient of 1/2x+1

1.	Obtain the differential coefficient of 1/2x+1
Answer» The DIFFERENTIAL coefficient of $\frac{1}{2x+1}$ is -2. Step-by-step explanation: Given : Expression $\frac{1}{2x+1}$ . To find : Obtain the differential coefficient of expression ? Solution : Applying DIVISION RULE of DIFFERENTIATION, $\frac{d}{dx}(\frac{u}{v})=\frac{vu'-uv'}{v^2}$ Here, u=1 and v=2x+1 $u'=\frac{d}{dx}(1)=0$ $v'=\frac{d}{dx}(2x+1)=2$ Substitute, $\frac{d}{dx}(\frac{1}{2x+1})=\frac{(2x+1)(0)-(1)(2)}{(2x+1)^2}$ $\frac{d}{dx}(\frac{1}{2x+1})=\frac{-2}{(2x+1)^2}$ Therefore, the differential coefficient of $\frac{1}{2x+1}$ is -2. #Learn more Differentiation of (3x+2) brainly.in/question/10499720

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