1.

Obtain a quadratic polynomial whose zeroes are 2α + β and α + 2β where α and β are the zeroes of x2 + 3x – 10.​

Answer»

ANSWER:

Hello DEAR User__________

Here is Your Answer...!!

____________________

Step by step SOLUTION:

Given \ p(x)=x^{2}+3x-10\\\\First \ let \ us \ solve\\\\p(x)=x^{2}+3x-10\\\\p(x)=x^{2}+5x-2x-10\\\\p(x)=x(x+5)-2(x+5)\\\\p(x)=(x+5)(x-2)\\\\\alpha=-5 \ and \ \beta=2\\ \\ putting \ in \ given \ zeroes\\\\2\alpha +\beta =-10+2=-8\\\\\alpha+2\beta=-5+4=-1\\ \\their \ sum=-8-1=-9 \ and \ their \ product=-8\times-1=8\\\\Required \ polynomial=x^{2}-(\alpha+\beta)x+\alpha \beta\\\\Required \ polynomial=x^{2}+9x+8

HOPE it is clear to you.


Discussion

No Comment Found

Related InterviewSolutions