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OB. If the perimeter of the following figure is 47 cm,fintIn fig, APBand AQP are semi-circles, and AO22]the area of the shaded region. | Useπ = |
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Answer» Let OA=OB =r.Therefore, 40= 22/7* r/2 + 22/7*r + r280= 40rr=7So, shaded area= (1/2*22/7*7/2*7/2 + 1/2*22/7*7*7)= 77/4 +77= 77 (1/4+1)= 77* 5/4= 385/4 cm^2= 96.25 cm^2 Like my answer if you find it useful! |
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