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o)seu0o Second order4)secondHow much time it require to complete161 For certain first order reaction, 75% of the reaction complete in 30 min.99.9% of the reaction?(2) 100 min(4) 300 min50 min(3) 90 minK is rate constant) |
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Answer» Order of reaction = 1Let the initial concentration be [A]0 = 100%[A]t = 100 -75 = 25%Rate law for first order rectionK = (2.303/t)log[A]0/[A]tfor (75%) - time is 30 minutes Substituting the values we get K = (2.303/30)*log[100/25]And k = 0.04621 per minute now % completion is 99.9 [A]t = 0.1% therefore t = (2.302/k)*log[100/0.1] t = (2.303/0.04621)*(3) = 149.5 = 150mins. |
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