O is any point in the interior of Δ ABC. Prove that(i) AB + AC > OB + OC(ii) AB + BC + CA > OA + OB + OC(iii) OA + OB + OC > 12(AB + BC + CA)

O is any point in the interior of Δ ABC. Prove that(i) AB + AC > OB +

1.	O is any point in the interior of Δ ABC. Prove that(i) AB + AC > OB + OC(ii) AB + BC + CA > OA + OB + OC(iii) OA + OB + OC > 12(AB + BC + CA)
Answer» O is any point in the interior of Δ ABC. Prove that (i) AB + AC > OB + OC (ii) AB + BC + CA > OA + OB + OC (iii) OA + OB + OC > $\frac{1}{2}$ (AB + BC + CA)