NumericalsHow many atoms are required to prepare 60g of HNO3 chemistry

1.	NumericalsHow many atoms are required to prepare 60g of HNO3 chemistry class 9Numerical 1.7
Answer» Answer: Mr of HNO3 is 1+14+316 = 63 60/63 = #of moles = 0.952380952 0.952380952 #Avogadro’s = #of molecules = 5.7142857x10^23 5.7142857x10^23 X #of ATOMS in ONE molecule = #of atoms = 2.8571429x10^24 atoms Explanation:

NumericalsHow many atoms are required to prepare 60g of HNO3 chemistry class 9Numerical 1.7

Answer»

Answer:

Mr of HNO3 is 1+14+3*16 = 63

60/63 = #of moles = 0.952380952

0.952380952 * #Avogadro’s = #of molecules = 5.7142857x10^23

5.7142857x10^23 X #of ATOMS in ONE molecule = #of atoms = 2.8571429x10^24 atoms

Explanation: