1.

Numbers of coulombs required to deposit 90 gm of aluminium, when the electrode fraction is,Al^3+3e^(-)toAl.....9.65times10^4,8.68times10^5,9.65times10^5,6.95.

Answer»

`9.65 XX 10^4`
`8.68 xx 10^5`
`9.65 xx 10^5`
`6..95`

ANSWER :C


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