Numbers Find a number whose double is 45 greater than its half.Find

1.	Numbers Find a number whose double is 45 greater than its half.Find a number such that when 5 is subtracted from 5 times the num.
Answer» ong>Answer: (i) Let the number be X. Double of x is 45 greater than its half (x/2). We can frame the equation as $2 \times x = 45+ \frac{x}{2}$ Transpose variables to ONE side, and constants to another side. $2x-\frac{x}{2} =45$ $\frac{3x}{2} = 45$ Transpose $\frac{3}{2}$ to the RHS. $x=\frac{2 \times 45}{3}$ $x=30$ (ii) the second question is incomplete. The question is: 5 is subtracted from 5 times the number, the result is 4 more than TWICE the number. Let the number be x. When 5 is subtracted from 5 times x, the result is 4 more than twice x. We can frame the equation as: 5x-5=4+2x Transpose variables to one side, constants to another side. 5x-2x=4+5 3x=9 x=9÷3 x=3 HOPE THIS HELPS