1.

Number of Solution of equation sin2 x -6sin x(a) 0+ 8 = 0 in R is(b) oo(c) 4(d) of

Answer»

let sinx = t

so, the equation becomes

t²-6t+8 = 0

=> t²-4t-2t+8 = 0=> t(t-4)-2(t-4) = 0=> (t-4)(t-2) = 0=> t = 4, 2

but since sinx can be greater than 1. so, no. of solutions will be 0.


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