Number of photon coming out per sec from the bulb of 100 watt.If it is

1.	Number of photon coming out per sec from the bulb of 100 watt.If it is 50% efficient and wavelength is 600nm
Answer» Answer: Explanation: RECALL E=hcλ E=(6.626×10−34)(3.0×108)560×10−9 E=3.550×10−19J Each PHOTON carries 3.550×10−19J of energy. A 100W SOURCE MEANS that it outputs 100J of energy every second. number of photons emitted = total energy output in one second / energy carried per photon n=1003.550×10−19=2.8×1020 (2sf)

Number of photon coming out per sec from the bulb of 100 watt.If it is 50% efficient and wavelength is 600nm

Answer»

Answer:

Explanation:

RECALL E=hcλ

E=(6.626×10−34)(3.0×108)560×10−9

E=3.550×10−19J

Each PHOTON carries 3.550×10−19J of energy.

A 100W SOURCE MEANS that it outputs 100J of energy every second.

number of photons emitted = total energy output in one second / energy carried per photon

n=1003.550×10−19=2.8×1020 (2sf)

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Number of photon coming out per sec from the bulb of 100 watt.If it is 50% efficient and wavelength is 600nm

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