1.

Number of natural life times (t_(av)) required for a first order reaction to complete 99.9% is

Answer»

`6.93`
`2.31`
`9.2`
infinite

Solution :`t_(99.9) = 10 xx t_(1//2)`
`=10 xx (0*693)/(k) ""(because t_(1//2) = (0*693)/(k))`
`=10 xx 0*693 xx t_(AV)"" (because t_(av) = (1)/(k))`
`= 6*93 xx t_(av), i.e., 6*93` natural life TIMES.


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