1.

Number of moles of K_(2)Cr_(2)O_(7) reduced by one mole of Sn^(2+) ions is

Answer»

`1/3`
`3`
`1/6`
`6`

Solution :`Cr_(2)O_7^(-2) + 3SN^(+2) RARR 3Sn^(+4) + 2Cr^(+3)`


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