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Number of hydrogen ions present in 10 million part of 1.33 cm of pure water at 25°C is(a) 6.023 million (b) 60 million(c) 8.01 million(d) 80.23 million​

Answer» 10 million=10-7so,10 millionth PART of 1.33cm3=1.33*10-7[H+]=10-7 MOL/litre1000 ml contain 10-7mole1 ml-----------=10-7/1000 mol 1.33*10-7ml=1.33*10-17no. of [H+]ions=1.33*10-17*6.023*10²³ =8.01millionRead more on Brainly.in - brainly.in/question/9768029#readmore


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