1.

Number of atoms of oxygen present in 10.6 g Na_(2)CO_(3)will be

Answer»

`6.022 xx 10^(22)`
`12.04 xx 10^(22)`
`1.806 xx 10^(23)`
`31.80 xx 10^(28)`

Solution :Molar mass of `Na_(2)CO_(3) = 2 xx 23 + 12 + 3 xx 16 = 106 g mol^(-1)`
`THEREFORE 10.6 g Na_(2)CO_(3) =0.1 mol`
`=0.1 xx 6.02 xx 10^(23)` molecules
`=3 xx 0.1 xx 6.02 xx 10^(23)` atoms of `O = 1.806 xx 10^(23)`


Discussion

No Comment Found

Related InterviewSolutions