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Number 136 is added to 5B7 and the sum obtained is 7A3, where A and B are integers. It is given that 7A3 is exactly divisible by 3. The only possible value of B is1. 22. 53. 74. 8 |
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Answer» Correct Answer - Option 4 : 8 Concept: The divisibility rule of 3 states that a number is completely divisible by 3 if the sum of its digit is divisible by 3 or multiple of 3. Calculation: ⇒ 7 + A + 3 = 10 + A (Possible value of A is 2, 5, 8) ⇒ 136 + 5B7 = 7A3 (Possible value of B is 6, 7, 8, 9) ⇒ For A = 2, B = 8 ⇒ 7 + 2 + 3 = 12, (Which is divisible by 3 or multiple of 3) ⇒ The value of B = 8 ∴ The required result will be 8. |
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