Nucleus A decays to B with decay constant lamda_(1) and B decuys to C with decay constants lamda_(2). Initially at t=0, number of nuclei of A and B are 2N_(0) and N_(0) respectively. At some instant t=t_(0), number of nuclei of B stop changing. Find t_(0) if at this intant number of nucleiof B is (3N_(0))/(2)

Nucleus A decays to B with decay constant lamda_(1) and B decuys to C

1.	Nucleus A decays to B with decay constant lamda_(1) and B decuys to C with decay constants lamda_(2). Initially at t=0, number of nuclei of A and B are 2N_(0) and N_(0) respectively. At some instant t=t_(0), number of nuclei of B stop changing. Find t_(0) if at this intant number of nucleiof B is (3N_(0))/(2)
Answer» `t_(0)=(1)/(lamda_(1))ln""(4lamda_(1))/(3lamda_(2))` `t_(0)=(1)/(lamda_(2))ln""(4lamda_(1))/(3lamda_(2))` `N_(A)=(3N_(0))/(2)(lamda_(2))/(lamda_(1))" to "t=t_(0)` `N_(A)=(2N_(0))/(3)(lamda_(2))/(lamda_(1))" at "t=t_(0)` Answer :OPTION 4

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