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ntIn YDSE ,the intensity of light at a point on the screen (where the path difference= lembda) is K ,(lembda being wavelength of light used) .The intensity at a point where the path difference is lemda/4 will ben

Answer» ntIn YDSE ,the intensity of light at a point on the screen (where the path difference= lembda) is K ,(lembda being wavelength of light used) .The intensity at a point where the path difference is lemda/4 will ben


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