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ntIn any triangle ABC, prove the following: asin[A/2].sin[(B-C)/2] + bsin[B/2].sin[(C-A)/2] + csin[C/2].sin[(A-B)/2] = 0n

Answer» ntIn any triangle ABC, prove the following: asin[A/2].sin[(B-C)/2] + bsin[B/2].sin[(C-A)/2] + csin[C/2].sin[(A-B)/2] = 0n


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