ntF(x+y)=f(x)+f(y),x,yR and f(1)=1. Then f(1)+ f(2)+ f(3)+. f(2009)=n – InterviewSolution

1.	ntF(x+y)=f(x)+f(y),x,yR and f(1)=1. Then f(1)+ f(2)+ f(3)+. f(2009)=n
Answer» ntF(x+y)=f(x)+f(y),x,yR and f(1)=1. Then f(1)+ f(2)+ f(3)+. f(2009)=n

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