1.

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Answer»

(n+1)P3 = 4*nP2 nPk = n!/(n-k)! using this formula (n+1)!/(n+1-3)! = 4*n!/(n-2)! (n+1)n!/(n-2)! = 4*n!/(n-2)! n+1 = 4 n = 4-1 n = 3

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