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Answer» te The answer of ur QUESTION is QUESTION 4.6 G of ethyl alcohol MIXED with 6g of acetic acid.Find out the value of Kc if 2g of acetic acid remains unused in chemical reaction.As we know that the , Equilibrium constant is the ratio of the product.Given EQUATION is here C2H5OH + CH3COOH->> CH3COOC2H5 + H2OKC = frac of [H2O]×[CH3COOC2H5][CH3COOH]×[C2H5OH]KC=2/3×2/3=4/9KC =0.44hope you got it |
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