Nitrogen and Hydrogen combine in the ratio of 14:3 by mass to form ammonia. What weight of nitrogen gas would be required to react completely with 9g of hydrogen gas? SA 2 IMP QUESTIONS

Nitrogen and Hydrogen combine in the ratio of 14:3 by mass to form amm

1.	Nitrogen and Hydrogen combine in the ratio of 14:3 by mass to form ammonia. What weight of nitrogen gas would be required to react completely with 9g of hydrogen gas? SA 2 IMP QUESTIONS
Answer» Molecular MASS of AMMONIA NH3 = mass of N + mass of H = 14 + 3 × 1 =17 To react with 14 g N mass of H required = 3 g Therefore to react with 42 g N mass of H required = 3/ 14 ×42 = 9G.

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Nitrogen and Hydrogen combine in the ratio of 14:3 by mass to form ammonia. What weight of nitrogen gas would be required to react completely with 9g of hydrogen gas? SA 2 IMP QUESTIONS​

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Nitrogen and Hydrogen combine in the ratio of 14:3 by mass to form ammonia. What weight of nitrogen gas would be required to react completely with 9g of hydrogen gas? SA 2 IMP QUESTIONS