Nitin bought some mangoes in such a way that selling price of 33 mango

1.	Nitin bought some mangoes in such a way that selling price of 33 mangoes is the same as the cost price of 44 mangoes. So the percentage of gain or loss is:1. 40%2. \(33{{1} \over 3}\)%3. 30%4. \(33{{2} \over 3}\)%
Answer» Correct Answer - Option 2 : \(33{{1} \over 3}\)% Given: SP of 33 mangoes = CP of 44 mangoes Formula used: P = S.P. – C.P. L = C.P. – S.P. P% = (P/C.P.) × 100 L% = (L/C.P.) × 100 Where, P → Profit L → Loss SP → Selling price CP → Cost price Calculations: Let the CP of 1 mangoe be Rs.y and its SP be x. So the SP of 33 mangoes = 33x And the CP of 44 mangoes = 44y According to the question, 33x = 44y ⇒ x ∶ y = 4 ∶ 3 Now let x and y be 4k and 3k respectively. Since x > y So P = 4k – 3k = k P% = (P/CP) × 100 ⇒ P% = (k/3k) × 100 = \(33{{1} \over 3}\)% ∴ The required Profit% is \(33{{1} \over 3}\)%.

Nitin bought some mangoes in such a way that selling price of 33 mangoes is the same as the cost price of 44 mangoes. So the percentage of gain or loss is:1. 40%2. \(33{{1} \over 3}\)%3. 30%4. \(33{{2} \over 3}\)%

Answer» Correct Answer - Option 2 : \(33{{1} \over 3}\)%

Given:

SP of 33 mangoes = CP of 44 mangoes

Formula used:

P = S.P. – C.P.

L = C.P. – S.P.

P% = (P/C.P.) × 100

L% = (L/C.P.) × 100

Where,

P → Profit

L → Loss

SP → Selling price

CP → Cost price

Calculations:

Let the CP of 1 mangoe be Rs.y and its SP be x.

So the SP of 33 mangoes = 33x

And the CP of 44 mangoes = 44y

According to the question,

33x = 44y

⇒ x ∶ y = 4 ∶ 3

Now let x and y be 4k and 3k respectively.

Since x > y

So P = 4k – 3k = k

P% = (P/CP) × 100

⇒ P% = (k/3k) × 100 = \(33{{1} \over 3}\)%

∴ The required Profit% is \(33{{1} \over 3}\)%.

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