1.

निम्न को सिद्ध कीजिए-(1 – sinθ) (1 + sin θ) (1 + tan2θ) = 1

Answer»

L.H.S. = (1 – sinθ) (1 + sinθ) (1 + tan2θ)

= (1 – sin2θ)sec2θ

= cos2θ · sec2θ

= cos2θ 1/cos2θ = 1 = R.H.S.



Discussion

No Comment Found