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निम्न को सिद्ध कीजिए-(1 – sinθ) (1 + sin θ) (1 + tan2θ) = 1 |
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Answer» L.H.S. = (1 – sinθ) (1 + sinθ) (1 + tan2θ) = (1 – sin2θ)sec2θ = cos2θ · sec2θ = cos2θ 1/cos2θ = 1 = R.H.S. |
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