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_ [नह00 कक 90500 [~ पए] नह 095500 * p uts घष्फ 9A01d ST |
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Answer» sinA/secA+tanA-1+ cosA/cosecA+cotA-1 =sinA/(1/cosA+sinA/cosA-1)+cosA/(1/sinA+cosA/sinA-1) =sinA/{(1+sinA-cosA)/cosA}+cosA/{(1+cosA-sinA)/sinA} =sinAcosA/(1+sinA-cosA)+sinAcosA/(1+cosA-sinA) =sinAcosA[(1+cosA-sinA+1+sinA-cosA)/(1+sinA-cosA)(1+cosA-sinA)] =2sinAcosA/(1+sinA-cosA+cosA+sinAcosA-cos²A-sinA-sin²A+sinAcosA) =2sinAcosA/{1+2sinAcosA-(sin²A+cos²A)} =2sinAcosA/(1+2sinAcosA-1) =2sinAcosA/2sinAcosA =1 (Proved) |
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