ngles of a triangle are in the ratio 4:4:2, find the value of each ang

1.	ngles of a triangle are in the ratio 4:4:2, find the value of each angle.X. If the angles or a than
Answer» let the angles be 4x,4x,2x the sum of all angles of a triangle is 180°. 4x+4x+2x=18010x=180x=18 so the angles are4×18=72°4×18=72°2×18=36° answer 1st angle is 72 2nd is also 72 and third angle is 36 4x+4x+2x=18010x=180x=180/10x=18°4x=4×18=72°4x=4×18=72°2x=2×18=36° answer

ngles of a triangle are in the ratio 4:4:2, find the value of each angle.X. If the angles or a than

Answer»

let the angles be 4x,4x,2x

the sum of all angles of a triangle is 180°.

4x+4x+2x=18010x=180x=18

so the angles are4×18=72°4×18=72°2×18=36° answer

1st angle is 72 2nd is also 72 and third angle is 36

4x+4x+2x=18010x=180x=180/10x=18°4x=4×18=72°4x=4×18=72°2x=2×18=36° answer