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Neumerical value of tan(20°)×tan(80°)×cot(50°) is equal to? |
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Answer» Answer: 0.8390996311 Step-by-step explanation: tan(80)=sin80/cos80=sin(90-20)/cos(90-20)=cos20/sin20 therefor sin20/cos20 * cos20/sin20 =1 =cot(50)*1 =cot 50=1/tan(50) =0.8390996311 |
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